0=7x^2-49x

Solution for 0=7x^2-49x equation:

0=7x^2-49x

We move all terms to the left:

0-(7x^2-49x)=0

We add all the numbers together, and all the variables

-(7x^2-49x)=0

We get rid of parentheses

-7x^2+49x=0

a = -7; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-7)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-7}=\frac{-98}{-14}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-7}=\frac{0}{-14}
=0
$